randRange( 2, 10 ) randRangeExclude( 2, 15, [ N1 ] ) localeToFixed( N1 * randRange( 80, 199 ) / 100, 2) (function() { var solutions = [ "\\dfrac{" + N1 + "}{\\$" + C + "} = \\dfrac{" + N2 + "}{x}", "\\dfrac{" + N2 + "}{x} = \\dfrac{" + N1 + "}{\\$" + C + "}", "\\dfrac{" + N1 + "}{" + N2 + "} = \\dfrac{\\$" + C + "}{x}", "\\dfrac{x}{" + N2 + "} = \\dfrac{\\$" + C + "}{" + N1 + "}" ]; return solutions; })() randFromArray([0, 1, 2, 2, 2, 3]) SOLUTIONS[ IDX ]

N1 deskItem( 0 ) cost $C.N1 plural_form(deskItem( 0 ), N1) cost $C.

Which equation would help determine the cost of N2 deskItem( 0 )?Which equation would help determine the cost of N2 plural_form(deskItem( 0 ), N2)?

`SOLUTION`

- `\dfrac{N2}{\$C} = \dfrac{x}{N1}`
- `\dfrac{N2}{N1} = \dfrac{\$C}{x}`
- `\dfrac{N1}{N2} = \dfrac{x}{\$C}`
- `\dfrac{x}{N2} = \dfrac{N1}{\$C}`
- `\dfrac{N2}{x} = \dfrac{\$C}{N1}`

There are several equations that could help determine the cost, each with a slightly different approach.

We can write the fact that N1 deskItem( 0 ) cost $C as a proportion:

We can write the fact that N1 plural_form(deskItem( 0 ), N1) cost $C as a proportion:

`\dfrac{N1}{\$C}`

Let `x` represent the unknown cost of N2 deskItem( 0 ). Since N2 deskItem( 0 ) cost `x`, we have the following proportion:

Let `x` represent the unknown cost of N2 plural_form(deskItem( 0 ), N2). Since N2 plural_form(deskItem( 0 ), N2) cost `x`, we have the following proportion:

`\dfrac{N2}{x}`

The cost changes along with the number of deskItem( 0 )s purchased, and so the two proportions are equivalent.

Let `x` represent the unknown cost of N2 deskItem( 0 ). Since N2 deskItem( 0 ) cost `x`, we have the following proportion:

Let `x` represent the unknown cost of N2 plural_form(deskItem( 0 ), N2). Since N2 plural_form(deskItem( 0 ), N2) cost `x`, we have the following proportion:

`\dfrac{N2}{x}`

We can write the fact that N1 deskItem( 0 ) cost $C as a proportion:

We can write the fact that N1 plural_form(deskItem( 0 ), N1) cost $C as a proportion:

`\dfrac{N1}{\$C}`

The cost changes along with the number of deskItem( 0 )s purchased, and so the two proportions are equivalent.

We know the cost of N1 deskItem( 0 ).We know the cost of N1 plural_form(deskItem( 0 ), N1). We want to know the cost of N2 deskItem( 0 ).We want to know the cost of N2 plural_form(deskItem( 0 ), N2). We can write the numbers of plural_form(deskItem( 0 )) as a proportion:

`\dfrac{N1}{N2}`

We know N1 deskItem( 0 ) costs $C.We know N1 plural_form(deskItem( 0 ), N1) costs $C. We can let `x` represent the unknown cost of N2 deskItem( 0 ).We can let `x` represent the unknown cost of N2 plural_form(deskItem( 0 ), N2). The proportion of these costs can be expressed as:

`\dfrac{\$C}{x}`

The cost changes along with the number of deskItem( 0 )s purchased, and so the two proportions are equivalent.

If we let `x` represent the cost of N2 deskItem( 0 ), we have the following proportion:

If we let `x` represent the cost of N2 plural_form(deskItem( 0 ), N2), we have the following proportion:

`\dfrac{x}{N2}`

We have to pay $C for N1 deskItem( 0 ), and that can be written as a proportion:

We have to pay $C for N1 plural_form(deskItem( 0 ), N1), and that can be written as a proportion:

`\dfrac{\$C}{N1}`

Since the price per deskItem(0) stays the same, these two proportions are equivalent.

`SOLUTIONS[ IDX ]`