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    "info": {
        "author": "Scott Chamberlain",
        "author_email": "sckott@protonmail.com",
        "bugtrack_url": null,
        "classifiers": [
            "Development Status :: 4 - Beta",
            "Intended Audience :: Developers",
            "Intended Audience :: Science/Research",
            "License :: OSI Approved :: MIT License",
            "Natural Language :: English",
            "Programming Language :: Python",
            "Programming Language :: Python :: 3",
            "Programming Language :: Python :: 3.5",
            "Programming Language :: Python :: 3.6",
            "Topic :: Scientific/Engineering :: Bio-Informatics"
        ],
        "description": "\n\npytaxa\n======\n\n|pypi| |travis| |coverage|\n\ninfo\n====\n\n* Minimum Python version: 3.5\n* pytaxa `docs <https://focused-neumann-123664.netlify.com/>`_\n* Check out sister R package: `taxa <https://github.com/ropensci/taxa>`_\n\nInstallation\n============\n\nStable version\n\n.. code-block:: console\n\n    pip install pytaxa\n    pip3 install pytaxa\n\nDev version\n\n.. code-block:: console\n\n    sudo pip install git+git://github.com/sckott/pytaxa.git#egg=pytaxa\n\n    # OR\n\n    git clone git@github.com:sckott/pytaxa.git\n    cd pytaxa\n    make install\n\nUsage\n=====\n\n.. code-block:: python\n\n    from pytaxa import constructors as cs\n    cs.taxon_name(\"Poa\")\n\n    from pytaxa import Taxon\n    x = Taxon(None)\n    x.is_empty()\n\n    name = cs.taxon_name(\"Poa\")\n    rank = cs.taxon_rank(\"genus\", \"ncbi\")\n    db = cs.taxon_database(\"ncbi\", \n      \"http://www.ncbi.nlm.nih.gov/taxonomy\",\n      \"NCBI Taxonomy Database\", \n      \"*\")\n    id = cs.taxon_id(12345, db)\n    tx1 = Taxon(name, rank, id, \"L.\")\n    tx2 = Taxon(cs.taxon_name(\"Poaceae\"), \n      cs.taxon_rank(\"family\", \"ncbi\"), cs.taxon_id(4479, db))\n    tx3 = Taxon(cs.taxon_name(\"Poa annua\"), \n      cs.taxon_rank(\"species\", \"ncbi\"), cs.taxon_id(93036, db))\n    from pytaxa import Taxa\n    Taxa(tx1, tx2, tx3)\n\n    from pytaxa import Hierarchy\n    out = Hierarchy(tx1, tx2, tx)\n    out.taxa\n    out.ranklist\n    out.all_empty()\n    out.pop(ranks = \"family\")\n\nContributing\n============\n\nSee `CONTRIBUTING.md <https://github.com/sckott/pytaxa/blob/master/.github/CONTRIBUTING.md>`_\n\nMeta\n====\n\n* Please note that this project is released with a `Contributor Code of Conduct <https://github.com/sckott/pytaxa/blob/master/CODE_OF_CONDUCT.md>`__. By participating in this project you agree to abide by its terms.\n* License: MIT; see `LICENSE file <https://github.com/sckott/pytaxa/blob/master/LICENSE>`__\n\n.. |pypi| image:: https://img.shields.io/pypi/v/pytaxa.svg\n   :target: https://pypi.python.org/pypi/pytaxa\n\n.. |travis| image:: https://travis-ci.org/sckott/pytaxa.svg?branch=master\n   :target: https://travis-ci.org/sckott/pytaxa\n\n.. |coverage| image:: https://codecov.io/gh/sckott/pytaxa/branch/master/graph/badge.svg\n   :target: https://codecov.io/gh/sckott/pytaxa\n\n\n\nChangelog\n=========\n\n0.0.6 (2018-06-26)\n--------------------\n* First pypi release\n\n\n",
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        "license": "MIT",
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        "name": "pytaxa",
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